Trukme

[Spag]

Kaip is amxbans patikrinti kiek liko iki ban pabaigos laiko? nu pvz.: (liko: 10h 10min 5s) čia su mysql man to gavimo ir tikrinmo reikia, pats nerandu kaip atimti iš dabartinio laiko ban_created...

[Tetusis]

pas mane toks yra

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<td>echo time_left($timeleft); ?></td>

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$timeleft = $CLIENT_BAN_DATE + $CLIENT_BAN_DURATION * 60 - time();

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function time_left($secondsLeft) {   $minuteInSeconds = 60;  $hourInSeconds = $minuteInSeconds * 60;  $dayInSeconds = $hourInSeconds * 24;   $days = floor($secondsLeft / $dayInSeconds);  $secondsLeft = $secondsLeft % $dayInSeconds;   $hours = floor($secondsLeft / $hourInSeconds);  $secondsLeft = $secondsLeft % $hourInSeconds;   $minutes= floor($secondsLeft / $minuteInSeconds);   $seconds = $secondsLeft % $minuteInSeconds;   $timeComponents = array();   if ($days > 0) {    $timeComponents[] = $days . " day" . ($days > 1 ? "s" : "");  }   if ($hours > 0) {    $timeComponents[] = $hours . " hour" . ($hours > 1 ? "s" : "");  }   if ($minutes > 0) {    $timeComponents[] = $minutes . " minute" . ($minutes > 1 ? "s" : "");  }   if ($seconds > 0) {    $timeComponents[] = $seconds . " second" . ($seconds > 1 ? "s" : "");  }   if (count($timeComponents) > 0) {    $formattedTimeRemaining = implode(", ", $timeComponents);    $formattedTimeRemaining = trim($formattedTimeRemaining);  } else {    $formattedTimeRemaining = "No time remaining.";  }   return $formattedTimeRemaining; }

[morka]

http://www.php.lt/render/Articles;aid,55

[Spag]

pas mane toks yra

Code: Select all

<td>echo time_left($timeleft); ?></td>

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$timeleft = $CLIENT_BAN_DATE + $CLIENT_BAN_DURATION * 60 - time();

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function time_left($secondsLeft) {   $minuteInSeconds = 60;  $hourInSeconds = $minuteInSeconds * 60;  $dayInSeconds = $hourInSeconds * 24;   $days = floor($secondsLeft / $dayInSeconds);  $secondsLeft = $secondsLeft % $dayInSeconds;   $hours = floor($secondsLeft / $hourInSeconds);  $secondsLeft = $secondsLeft % $hourInSeconds;   $minutes= floor($secondsLeft / $minuteInSeconds);   $seconds = $secondsLeft % $minuteInSeconds;   $timeComponents = array();   if ($days > 0) {    $timeComponents[] = $days . " day" . ($days > 1 ? "s" : "");  }   if ($hours > 0) {    $timeComponents[] = $hours . " hour" . ($hours > 1 ? "s" : "");  }   if ($minutes > 0) {    $timeComponents[] = $minutes . " minute" . ($minutes > 1 ? "s" : "");  }   if ($seconds > 0) {    $timeComponents[] = $seconds . " second" . ($seconds > 1 ? "s" : "");  }   if (count($timeComponents) > 0) {    $formattedTimeRemaining = implode(", ", $timeComponents);    $formattedTimeRemaining = trim($formattedTimeRemaining);  } else {    $formattedTimeRemaining = "No time remaining.";  }   return $formattedTimeRemaining; }

O kaip pasidaryti, kad dar tikrintų jeigu hours daugiau negu 9?

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($hours > 1 ? "text_1" : "text_2")

taip pasidariau, bet neveikia:

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($hours > 9 > 1 ? "text_1" : "tex_2" : "text_3")

[V1LKAS]

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if($hours > 1){  echo "text_1:";}

Ta prasme taip tu nori?

[Tetusis]

if($hours > 1){
echo "text_1:";
}

Ta prasme taip tu nori?

daugiau nei 9

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if($hours > 9){  echo "text_1:";}

[V1LKAS]

if($hours > 1){
echo "text_1:";
}

Ta prasme taip tu nori?

daugiau nei 9

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if($hours > 9){  echo "text_1:";}

[Tetusis]

if($hours > 1){
echo "text_1:";
}

Ta prasme taip tu nori?

daugiau nei 9

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if($hours > 9){  echo "text_1:";}

[aaarnas]

Netestavau, bet gerai turėtų veikti. Į funkciją reikia perduoti minučių skaičių "ban_lenght"

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<?phpfunction print_time($minutes) {        $weeks = (int)($minutes/10080);    $minutes -= $weeks*10080;    $days = (int)($minutes/1440);    $minutes -= $days*1440;    $hours = (int)($hours/60);    $minutes -= $hours*60;        echo $weeks?($weeks." sav. "):"".         $days?($days." dien. "):"".         $hours?($hours." val. "):"".         $minutes?($minutes." min. "):"";}?>